A noodles merchant buys two varieties of noodles the price of the first being twice that of the second. He sells the mixture at Rs 17.50 per kilogram thereby making a profit of 25%. If the ratio of the amounts of the first noodles and the second noodles in the mixture is 2:3, then the respective costs of each noodles are
Answer: A let the price of one noodles = k => the price of other noodle = k/2 Price of 1 kg = 2k/5 + (3/5*k/2) = 7k/10 But CP = 17.50*100/125 = 14 => 7k/10 = 14 => k = 20 So price of the noodles's are 20 and 10.
Q. No. 14:
There are certain number of toys in the box. they are divided into such a way that the person who gets 1/4 of the whole gets thrice of what the others get on an average. Find the number of people amongst whom the toys are distributed?
Answer: B If the person who gets 1/4 of the whole gets thrice of what the others get on an average, each one will get = 1/3 * 1/4 = 1/12 of the whole. Therefore, if there are k persons other than the person who gets one-fourth, then 1/4 + k/12 = 1 => k =9 Hence, total number of people = 10.
Q. No. 15:
Three beakers have capacity of 250ml, 650ml and 200ml. 682 ml of Juice is poured into them so that the same fraction of each is filled. The volume filled in the largest beaker will be
Answer: B As the beaker filled by the same fractions, p/250 = q/650 = r/200 = (p+q+r)/(250+650+200) Thus p+q+r = 682 => q = 403 ml.
Q. No. 16:
Two man, sitting on the dining table. One men has 7 eggs and other had 5 eggs. A third man passing by requested them to share their food in return for money. The three of them shared the eggs equally and the the third traveller paid the other two a total of Rs 24. Find the difference between the amounts received by first two man?
Answer: B As the two man had a total of 12 eggs. The first and the second man must have given 3 eggs and 1 eggs to the third man. Hence, the ratio of their share must be 3:1. Hence the first and the second man get Rs 18 and Rs 6 respectively. The 1st man get Rs 12 more than the second.
Read the following information to answer the questions that follow :
The cost of fuming the engine of an army tank is proportional to the square of the speed and Rs 64 per hour for a speed of 16km/hr. Other costs amount to Rs 400 per hour. The tank has to make a journey of 400km at a constant speed.
Answer: D Cost =k* (speed)2 [where k is constant]
=> 64 = k*16*16
=> k = 1/4
Cost = (speed)2 /4
Total cost = cost of fuel* time + other cost* time
= (speed)2 /4 * distance/speed + 400*
distance/speed
Total cost = [(speed)2 /4 + 400] * 400/speed
using options, putting different values of speed, we find speed = 40km/hr to be most economical. Alternative: d(total cost)/d(speed) = 0
Given, v = 40km/hr.
Q. No. 2:
The total cost for the journey at this most economical speed is :
Answer: B Cost =k* (speed)2 [where k is constant]
=> 64 = k*16*16
=> k = 1/4
Cost = (speed)2 /4
Total cost = cost of fuel* time + other cost* time
= (speed)2 /4 * distance/speed + 400*
distance/speed
Total cost = [(speed)2 /4 + 400] * 400/speed
using options, putting different values of speed, we find speed = 40km/hr to be most economical. Alternative: d(total cost)/d(speed) = 0
Given, v = 40km/hr. Total cost = [(40)2 /4 + 400] * 400/40 = Rs 8,000.
Q. No. 18:
A,B and C enter into a partnership by investing Rs 28000, Rs 32000 and Rs 18000. A is working partner and gets a fourth of the profit for this services and the remaining profit is divided amongst the three in the ratio of their investments. What is the amount of profit that B gets if A gets a total of Rs 4995 ?